Question #2ef1a

1 Answer
bp
Feb 1, 2018

13.7 kms approx

Explanation:

The diagram showing the position of the balloon, the two buildings and the angles of depression as described in the question is shown below:

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From rt. triangle CBD, BD= 3 cot 82 kms and from rt. triangle CAD, AD= 3 cot 12 kms

The distance between the two buildings is AB= AD-BD= 3(cot 12- cot 82)

= 3#(tan 82 - tan12)/(tan82 tan 12)#

= 3#(7.1153-0.2125)/((7.1153) (0.2125))#

=13.7 kms approx

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