What is #2 4/8# plus #6 5/7# as a mixed number?

2 Answers
Feb 1, 2018

See a solution process below:

Explanation:

First, convert both numbers from a mixed number to an improper fraction:

#2 4/8 = 2 1/2 = 2 + 1/2 = (2/2 xx 2) + 1/2 = 4/2 + 1/2 = (4 + 1)/2 = 5/2#

#6 5/7 = 6 + 5/7 = (7/7 xx 6) + 5/7 = 42/7 + 5/7 = (42 + 5)/7 = 47/7#

To add fractions they must be over a common denominator. We can multiply each improper fraction by the appropriate form of #1# to put the fractions over a common denominator without changing the value of the fractions:

#5/2 xx 7/7 = (5 xx 7)/(2 xx 7) = 35/14#

#47/7 xx 2/2 = (47 xx 2)/(7 xx 2) = 94/14#

We can next add the two fractions:

#35/14 + 94/14 = (35 + 94)/14 = 129/14#

We can now convert this improper fraction into a mixed number:

#129/14 = (126 + 3)/14 = 126/14 + 3/14 = 9 + 3/14 = 9 3/14#

Feb 1, 2018

#9 3/14#

Explanation:

I would first change everything into a improper fraction. To do this, you are going to multiply the denominator by the whole number, and then add it to the numerator.

#8*2+4=20/8#

#7*6+5=47/7#

Now you need to make both of the denominators the same. To do this you will multiply the #20/8# by #7#, and the #47/7# by #8#. Remember, what you do to the top, you have to do to the bottom.

#8*7=56#
#20*7=140#
#140/56#

#7*8=56#
#47*8=376#
#376/56#

Then you need to add both numerators together. The denominator will stay the same number which in this case is #56#.

#140/56+376/56=516/56#

The last thing you need to do is divide #516# and #56# together.
Your mixed number will then be
#9 3/14#