Question #4f976

1 Answer
Feb 1, 2018

#4x^2+5x-1#

Explanation:

Input the variables in the correct area...
#(x+1)(2x+2x-1)+(2x)#
The first part is to use the distributive property to distribute #(x+1)# into #(2x+2x-1)#, you can just add 2x+2x to equal 4x. You should get #4x^2+3x-1#...
now input your answer to the question,
#(4x^2+3x-1)+(2x)#
Since you are adding both equations you can automatically take down the parenthesis...
#4x^2+3x-1+2x#
Use P.E.M.D.A.S. to finish your answer,
Parenthesis, we have none.
Exponents, we cant do anything with it.
Multiplication, we can't do anything with multiplication because we need the value of x.
Addition, we can add 2x plus 3x because they have the same base...
#4x^2+5x-1#
Subtraction, we have no subtraction available in this equation...
and we can't do anything more because:
- if the base number has an exponent, to add to the number, we would need another number with the same exponent.
-we can't subtract anything because we don't know the value of x
-etc.
Hope this helped... Comment if you have any further questions