Question

Question #1b7e2

Answer 1

This solution is supersaturated. Explanation below...

Explanation:

The graph you have reads "g of solute per 100 g `H_2O`. Therefore, the information we are given (42 g in 50 mL) needs to be altered.

The same rate of dissolving would result in 84 g in 100 g `H_2O`

Now, find 84 g on the vertical scale, and draw a horizontal line from that point across the graph. Then draw a vertical line up from 30 °C, and you will see that the intersection of these lines is at a point above and to the left of the green curve for `KNO_3`.

Being in this region means that the amount of solute is greater than the saturation point (which would fall on the curve - at about 44 g at 30°C) for `KNO_3`.

Therefore, the solution is supersaturated - an unstable situation in which you manage to dissolve more solute than saturation would seem to allow!