Question

Question #2a70b

Answer 1

`~~2.41*10^24` particles

Explanation:

Assuming that you are saying `64g` of `O` (single oxygen) atoms:

Oxygen has a molar mass of `16g"/"mol`.

`:.64g` of oxygen atoms is `(64g)/(16g"/"mol)=4mol`

One mole is `6.02*10^23` particles/atoms.

`:. 4mol=4*6.02*10^23~~2.41*10^24` oxygen atoms.

Answer 2

`~2.41*10^24` atoms

Explanation:

To find the number of particles (in this case atoms), we need to find the number of moles of oxygen atoms.

`n(O)=(m(O))/(M_r(O))=64/16=4mol`

`"Number of particles"=n*N_a`, where `N_a` is Avogadros' constant (`6.02*10^23` `mol^(-1)`)

`"Number of oxygen atoms"=n(O)*N_a`
`color(white)("Number of oxygen atoms")=4(6.02*10^23)~~2.41*10^24` atoms

Answer 3

It's `2.4092 xx 10^24` particles in `64` g of Oxygen atom.

Explanation:

Since we have `O` = `16` g = `1` mole= `6.023 xx 10^23` particles, so on this basis, when we have 64g of O, which is the `4 xx16`, so it will be `4` moles, and `4` moles= `4 xx 6.023 xx 10^23` .. which is eventually `2.4092 xx 10^23` atoms in `O`.

Hope this helps.. :)