If #sqrt(a^2+b^2)=c^(1/2)#, Find values for a and b?

Question

The first step is to square both sides, but I can't think of anything next
(assuming #c# is a constant)

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Answer 1 · 2018-02-02T21:50:38

#a=+-sqrt(c-b^2)#

We want to solve for #a# in

#sqrt(a^2+b^2)=c^(1/2)#

Square both sides

#a^2+b^2=c#

Subtract #b^2# from both sides

#a^2=c-b^2#

Take the square root on both sides

#a=+-sqrt(c-b^2)#

By similar approach you could find #b#