Question #e94ae

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Answer 1 · 2018-02-03T11:45:44

$6$ metres.

Preparing a $1$ metre wall costs $rarr$ Rs. $1.35$

So, It will cost Rs. $340.20$ to prepare walls of total $340.2/1.35$ $m^2$ = $252$ $m^2$

So, The total area of the walls = $252$ $m^2$

And It costs Rs. $0.85$ for matting a floor of $1$ $m^2$ .

So, It costs Rs. $91.8$ for matting a floor of $91.8/0.85$ $m^2$ = $108$ $m^2$

We are given the length of the room is = $12$ metres.

So, the width of the room is $108/12$ metres = $9$ metres.

Now, Let's assume that the height of the room is $h$ metres.

Now, According to the problem,

$2(12 + 9) xx h = 252$ [The total surface area formula]

$rArr 2(21) xx h = 252$

$rArr 42h = 252$

$rArr h = 252/42 = 6$

So, The height of the room is $6$ metres.

Hence Explained.