Question #3f769

Question

213 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-05T00:26:36

I got #pH=12#

Well first, we have to calculate the molarity of the solution.

So, #0.4g# of #NaOH# is equal to

#0.4/40=0.01mol \ NaOH#

So, the concentration will be #0.01M#.

Since sodium hydroxide is a base, we need to calculate the #pOH# of the solution, and then subtract using the following equation:

#pH+pOH=14# (assuming T=298K#).

So, the #pOH=-log[0.01]=2#

#:.[pH](https://socratic.org/chemistry/acids-and-bases/the-ph-concept)=14-2=12#