Question #bb2ac

1 Answer
Sam F.
Feb 7, 2018

#sinx+xcosx+sec^2x#

Explanation:

The first term of the derivative can be simplified to #xsinx#. This is why you spend all those agonizing hours doing trig identities!

#xtanx/secx = (xsinx/cosx)/(1/cosx) = xsinx/cosx*cosx=xsinx#

So now your function looks like this:

#xsinx+tanx#

Take the derivative of each term separately, using the product rule for the first term.

#(sinx +xcosx)+sec^2x#

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