How do you solve #-65\geq 5- 2( 3- 4x )#?

1 Answer
Jim G.
Feb 7, 2018

#x<= -8#

Explanation:

#"distribute the bracket on the right side of the inequality"#

#-65>=5-6+8x#

#rArr-65>= -1+8x#

#"add 1 to both sides"#

#-65+1>=cancel(-1)cancel(+1)+8x#

#rArr-64>=8x#

#"divide both sides by 8"#

#rArr-8>=xrArrx<= -8#

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