Question #e10c9

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Answer 1 · 2018-02-07T17:22:03

x = +-1

So, first apply the slope formula to your equation given your two end points.

#{2^3-(-1)^3}/{2--1}#= #{8+1}/3#=3

That's the slope of the line between your two points. This is also the Average Rate of Change between those points.

What we need to find is where the tangent line of #x^3# is going to have a slope of 3.

So, first find the derivative = #f'(x) = 3x^2#

Set that equal to 3, so #3=3x^2#

Then, #1=x^2; x = +-1#