Question #de587

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Answer 1 · 2018-02-08T01:19:30

#x=7#

Use the property of logs, in this case the quotient rule:

#log_b(m/n)=log_b(m)-log_b(n)#

So:

#log_3((3x+6)/(x-4))=2#

Here is the basic form of a logarithm:

#log_b(a)=c hArr b^c=a#

Using this rule, you get this:

#9=(3x+6)/(x-4)#

Cross multiply:

#9x-36=3x+6#

Solve for x:

#6x=42#

#x=7#

Have a nice day!