Question #426b2

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Answer 1 · 2018-02-08T08:30:55

#5#

#y=2x^2-2x#

First we need to differentiate the function. We can do this for this function using the power rule:

#dy/dxax^n=nax^(n-1)#

Notice that:

#dy/dx (ax^2+bx)=dy/dxax^2+dy/dxbx#

#dy/dx2x^2-2x=2*2x^(2-1)-1*2x^(1-1)=4x-1#

So our derivative is:

#f^'(x)=4x-1#

We now plug in the value #x=1.5#:

#f^'(1.5)=4(1.5)-1=5#

#bb5# is the gradient of a tangent line drawn at #bb(x=1.5)#

GRAPH:

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