#lim_(xto0)(4-x^2)/(5-x^2)#?

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Answer 1 · 2018-02-08T09:10:20

#4/5#

This is easily solved by just plugging in #x=0#

#(4-(0)^2)/(5-(0)^2)=4/5#

#:.#

#lim_(x->0)(4-x^2)/(5-x^2)=4/5#

Answer 2 · 2018-02-08T10:40:38

#4/5#

#"find the limit using "color(blue)"direct substitution"#

#rArrlim_(xto0)(4-x^2)/(5-x^2)=(4-0)/(5-0)=4/5#