Question #531b1

1 Answer
Feb 9, 2018

0.995%

Explanation:

Here is a derived equation I found.

#T=4mLf^2#
#f=sqrt(T/(4mL)#

So, if you plug in 1.02 next to T for tension we see that #f=sqrt((1.02T)/C#

therefor the #Deltaf# will be #1.00995# or about #0.995%#