Question #d1400

1 Answer
zhirou
Feb 10, 2018

#"1.3J/g°C"#.

Explanation:

For this question, we should use #q=mCDeltaT#, where #q# is heat gained or lost, #m# is mass, #C# is specific heat, and #DeltaT# is temperature change.

#q# would be #"45.1J"#.
#m# would be #"1.2g"#.
#DeltaT# would be #"final - initial" = 80 - 50 = "30°C"#.

Let's plug that into #q=mCDeltaT# to solve for #C#:

#"45.1J" = "1.2g" xx C xx 30°C#
#C = "45.1J" / ("1.2g" xx 30°C)#
#C = 1.25277778 = "1.3J/g°C"#

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