Question

How `H_2SO4+NaOH` could be `Na_2SO4+H_2O` and how to balance it?

Answer 1

It will be `H_2SO_4 + 2NaOH -> Na_2SO_4 + 2H_2O`

Explanation:

You begin with `H_2SO_4 + NaOH -> Na_2SO_4 + H_2O`.
Notice that there are 2 `Na`'s on the right side. This means you need to add a coefficient of 2 in front of `NaOH` to balance the `NA`'s. Now, you count the `H`'s. You'll find that there are 4 on the left and only 2 on the right. To balance the `H`'s, add a coefficient of 2 infront of `H_2O`.

Answer 2

See the explanation

Explanation:

`H_2SO_4` is an acid while `NaOH` is a base.

An acid and a base react to give salt of the acid and water.

So, sulphuric acid (`H_2SO_4`) react with sodium hydroxide (`NaOH`) to give sodium sulphate
(`Na_2SO_4`) which is a salt and water.

This reaction is also called neutralization reaction.

For balancing it, there should be equal number of each atom on both the sides.

The balanced equation is:-

`H_2SO_4 + 2NaOH -> Na_2SO_4 + 2H_2O`