8 g NaOH is dissolved in 250 ml solution. If solution is diluted to 500 ml then moles of NaOH and molarity of dilute solution would be ?

1 Answer
Feb 11, 2018

The concentration would be halved....

Explanation:

In either scenatio, we gots "concentration"="moles of solute"/"volume of solution"concentration=moles of solutevolume of solution

"concentration"_1=((8.0*g)/(40.0*g*mol^-1))/(250*mLxx10^-3*L*mL^-1)concentration1=8.0g40.0gmol1250mL×103LmL1

=0.80*mol*L^-1=0.80molL1

"concentration"_2=((8.0*g)/(40.0*g*mol^-1))/(500*mLxx10^-3*L*mL^-1)concentration2=8.0g40.0gmol1500mL×103LmL1

=0.40*mol*L^-1=0.40molL1...