Question #13273

1 Answer
Jake A.
Feb 11, 2018

0 grams of chlorine are produced

However I assume you meant fluorine, so:

#PV=nRT#

#n=(PV)/(RT)#

#n=((1.00atm)(2.01L))/((0.08206L*atmK^-1mol^-1)(273.15K))=0.0897 mol F_2#

#F_2 -> 37.996 g/(mol)#

#(0.0897 mol )(37.996 g/(mol)) = 3.41 g#

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