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Answer 1 · 2018-02-12T03:54:04

#0.05# moles of #N_2H_6CO_2#

Well, we would first need to calculate the molar mass of #N_2H_6CO_2#.

#N# has a molar mass of #14g"/"mol#.

#:.N_2# has a molar mass of #28g"/"mol#.

#H# has a molar mass of #1g"/"mol#.

#:.H_6# has a molar mass of #6g"/"mol#.

#CO_2# has a molar mass of #44g"/"mol#.

#:.N_2H_6CO_2# has a molar mass of #28+6+44=78g"/"mol#.

#"moles"="mass"/"molar mass"#

#:."moles"=(4cancelg)/(78cancelg"/"mol)=0.05mol#