Question #38190

1 Answer
Feb 13, 2018

The answer is #tanx+xsec^2x#

Explanation:

Using the product rule for differentiation ,
#dy/dx=xtanx#
Let x=u and v=tanx

By product rule ,
#dy/dx= v.du/dx + u.dv/dx# ------(i)

Now , #du/dx=1# and #dv/dx=sec^2x#

Substituting these into (i) you get ,
#dy/dx=tanx+xsec^2x#

#:.# The answer is #tanx + xsec^2x#