If #Log_y6=x#, #Log_y3.5=z# and #6a=3.5# then #a=??#
If #Log_y6=x# , #Log_y3.5=z# and #6a=3.5# then #a=??#
#(a)# #xz#
#(b)# #z/x#
#(c)# #z+x#
#(d)# #z-x#
I searched on internet about correct answer and it was #(b)# #z/x# , but I don't know why #(b)# is correct. I think that all the answers listed are incorrect.
If
I searched on internet about correct answer and it was
1 Answer
Feb 15, 2018
I got
Explanation:
We're told that
We can rearrange these equations to put them into exponential form:
And substitute in the values: