Question #44f31

1 Answer
Feb 16, 2018

The integers are #19,20,21,22#

Explanation:

Let.... the second consecutive integer be #x#
Then the first integer would be #x-1#
The third integer would be #x+1#
Then.... the fourth integer would be #x+2#

Now the first and the fourth integer add up to #41#

Jot it down in one equation
#x-1+x+2=41#

Solve
#2x+1=41#

Transfer 1
#2x=40#

Divide by 2
#x=40/2#

#color(red)(x=20" "# this is the second integer
Then...
The first integer is #color(red)(x-1rArr20-1rArr19#
Then the third integer would be #color(red)(x+1rArr20+1rArr21#
Then the fourth integer will be #color(red)(x+2rArr20+2rArr22#