Can you please help answer this? Solid lead (II) iodide forms when aqueous solutions of potassium iodide and lead (II) nitrate are mixed. Write the molecular equation and include state symbols.

Please explain how you got the answer.

1 Answer
Umer F.
Feb 17, 2018

#Pb(NO_3)_2 + 2KI\rightarrow PbI_2 + 2 KNO_3#

Explanation:

Lead (II) iodide or lead iodide is a salt with the formula #PbI_2#. At room temperature, it is a bright yellow odorless crystalline solid, that becomes orange and red when heated. It was formerly called plumbous iodide.
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Preparation:

#PbI_2# is commonly synthesized via a double displacement reaction between potassium iodide #KI# and lead(II) nitrate #Pb(NO_3)_2# in water solution:

#Pb(NO_3)_2 + 2KI\rightarrow PbI_2 + 2 KNO_3#

While the potassium nitrate #KNO_3# is soluble, the lead iodide #PbI_2# is nearly insoluble at room temperature, and thus precipitates out.

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**Read more about it, **"https://en.wikipedia.org/wiki/Lead(II)_iodide"

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