First, add #color(red)(14)# to each side of the inequality to isolate the #v# term while keeping the inequality balanced:
#4 + color(red)(14) > 15v - 14 + color(red)(14)#
#18 > 15v - 0#
#18 > 15v#
Next, divide each side of the inequality by #color(red)(15)# to solve for #v# while keeping the equation balanced:
#18/color(red)(15) > (15v)/color(red)(15)#
#(6 xx 3)/color(red)(5 xx 3) > (color(red)(cancel(color(black)(15)))v)/cancel(color(red)(15))#
#(6 xx color(red)(cancel(color(black)(3))))/color(red)(5 xx color(black)(cancel(color(red)(3)))) > v#
#6/5 > v#
We can reverse or "flip" the entire inequality to state the solution in terms of #v#:
#v < 6/5#