Given that lim_(x->oo)((x^2)/(1+x)-ax-b), find the values of a and b ?

1 Answer
Feb 19, 2018

See below.

Explanation:

We have

x^2 = (x+1)(x-1)+1 then

lim_(x->oo)(x^2/(x+1)-ax-b) = lim_(x->oo)((x-1)+1/(x+1)-ax-b) =

=lim_(x->oo)(x-1-ax-b) Now choosing a=1 we get

lim_(x->oo)(x^2/(x+1)-(1)x-b)=-(b+1)