Question

Percentage of nitrogen in magnesium nitrade is?

Answer 1

Approx. `28%`

Explanation:

For `Mg_3N_2`. `%N="mass of nitrogen"/"molar mass of magnesium nitride"xx100%`

`=(2xx14.01*g*mol^-1)/(100.95*g*mol^-1)xx100%=27.8%`