How do you solve these? please help. I need to find the period and I am so lost! Y= cot2 (x) Thank you!

1 Answer
Feb 20, 2018

For the first function \ \ \ y=cot[2(x)]\ \ \

\text{Period}=\frac{\pi }{2}

Explanation:

Consider the general form of periodic function:

y\ =\ a\cot (bx\pm c)\pm d

The period of a periodic function can be calculated by the formula:

\text{Period}\ =\ \frac{\text{periodicity of base}}{|b|}

We know that the periodicity of the sin(x), cos(x), csc(x) and sec(x) is 2pi while that of tan(x) and cot(x) is pi.

So, for our given function y=cot[2(x)], we have:

a=1, b=2, c=0 and d=0

So, the required period of this function is:

\text{Period}=\frac{\pi }{|2|}

=\frac{\pi }{2}

Try others by yourself. They are not that hard!