Power series help?
n
SUM 3k(k^2+4),
k=1
give answer in form 3/4n(n+1)(An^2+Bn+C)
k=1
n
SUM 3k(k^2+4),
k=1
give answer in form 3/4n(n+1)(An^2+Bn+C)
k=1
1 Answer
Feb 20, 2018
See below.
Explanation:
If
then
now solving
for