Question

Question #7f679

Answer 1

The maximum profit is $91 with 30 employees.

Explanation:

Let the amount of money be $y.

Given `y=-0.1x^2+6x+1`
`y=-0.1(x^2-60x)+1`
`y=-0.1[(x-30)^2-900]+1`
`y=-0.1(x-30)^2+91`

When `x` deviates from 30,
`(x-30)^2>0`
And the respective value of y will decrease.

Hence, to maximize the profit, x should be as close to (and should be) 30, which by substitution,

`y=91`