Question

An object with a mass of `5 kg` is on a plane with an incline of `pi/8`. If the object is being pushed up the plane with `15 N` of force, what is the net force on the object?

Answer 1

`-3.77 \ "N"`

Explanation:

The net force of this object will take the form of

`F_"net"=F_"applied"+F_"inclined"`

Here, the inclined force will be `F=mg sintheta`

Since it is opposite to the direction of the push, it will be negative, i.e. `-mgsintheta`

So, the equation becomes

`F_"net"=F_"applied"-mgsintheta`

Plugging in the given values, we get

`F_"net"=15 \ "N"-5 \ "kg"*9.81 \ "m/s"^2*sin(pi/8)`

`F_"net"=15 \ "N"-18.77 \ "N"`

`F_"net"=-3.77 \ "N"`

So, the net force will be `3.77 \ "N"` to the opposite direction of the push.