How many grams are in 2.3 xx 10^4color(white)(l)"mol" of calcium phosphate, Ca3(PO4)2?

1 Answer
Feb 22, 2018

7136900 "g" or 7136.9 "kg"

Explanation:

Assuming you mean that we have 2.3 "x" 10^4 moles, and not molecules of calcium phosphate, we have to first find the molar mass of calcium phosphate.

MW = "Mass of Ca"*3+"Mass of P"*2+"Mass of O"*8
MW = 40.1*3+31*2+16*8
MW = 310.3 "g"/"mol"

So now we multiply that number by the number of moles we have:

2.3 "x" 10^4 "moles" * 310.3 "g"/"mol"
2.3 "x" 10^4 color(red)(cancel("moles"))*310.3 "g"/color(red)(cancel("moles"))
7136900 "g" or 7136.9 "kg"

Hope this helps!