Question

How many grams are in `2.3 xx 10^4color(white)(l)"mol"` of calcium phosphate, Ca3(PO4)2?

Answer 1

`7136900 "g"` or `7136.9 "kg"`

Explanation:

Assuming you mean that we have `2.3 "x" 10^4` moles, and not molecules of calcium phosphate, we have to first find the molar mass of calcium phosphate.

`MW = "Mass of Ca"*3+"Mass of P"*2+"Mass of O"*8`
`MW = 40.1*3+31*2+16*8`
`MW = 310.3 "g"/"mol"`

So now we multiply that number by the number of moles we have:

`2.3 "x" 10^4 "moles" * 310.3 "g"/"mol"`
`2.3 "x" 10^4 color(red)(cancel("moles"))*310.3 "g"/color(red)(cancel("moles"))`
`7136900 "g"` or `7136.9 "kg"`

Hope this helps!