Question

How to solve `6^x-2^x-2*3^x+2=0`?

Answer 1

`x=0, x=1`

Explanation:

`6^x-2^x-2*3^x+2=0`
`2^x(3^x-1)-2(3^x-1)=0`
`(3^x-1)(2^x-2)=0`
`3^x-1=0`
`3^x=1` => `x=0`
`2^x-2=0`
`2^x=2`=> `x=1`
thus:
`x=0, x=1`