Given f(x) = 2x^2 - 3, what is its domain, range and y-intercept?

1 Answer
Feb 24, 2018

Domain: (-oo, oo)
Range: [-3,oo)
y-intercept : (0,-3)

Explanation:

Domain of f(x) is the set of points where f(x) is defined.
So, f(x)=2x^2-3 is defined for all real values of x,
hence domain is given by (-oo,oo).

The minimum value of f(x) is at x=0
f(0)=2(0)^2-3=-3
The maximum value of function is at oo
so range is [-3.oo).

the function intercepts at y-axis at a point where x=0,
so f(0)=-3
ie (x,y)=(0,-3).