How do you find the limit of #3x+2# as #x->-3#?

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Answer 1 · 2018-02-25T11:58:49

There is no problem with evaluating the expression at #x = -3#; doing so will give us the value of the limit.

#L = lim_(x to -3) 3x +2#

#L = 3(-3) +2#

#L = -7#

Answer 2 · 2018-02-25T12:00:23

#-7#

#"the limit can be evaluated by direct substitution"#

#rArrlim_(xto-3)3x+2=-9+2=-7#