Question #6cbbb

2 Answers
Feb 25, 2018

CuO(s)+2HCl(aq)->CuCl_2(aq)+H_2O(l)

Explanation:

This is a neutralization reaction. In a neutralization reaction, the chemical equation is as follows:

"acid + base" \ -> \ "salt + water"

Here, we got CuO as a base, since it can react with water to form Cu(OH)_2, which is a basic solution. The acid here is HCl.

So, our reaction will be

CuO(s)+HCl(aq)->CuCl_2(aq)+H_2O(l)

To balance it, I see 2 chlorines on the right side, while only one on the left side, so I multiply HCl by 2. This gives us:

CuO(s)+2HCl(aq)->CuCl_2(aq)+H_2O(l)

This is also a reaction that has been covered here:

https://socratic.org/questions/cuo-s-hcl-aq-equation-and-net-ionic-equation

Feb 25, 2018

"CuO" + "2HCl" rarr "CuCl"_2+"H"_2"O"

Explanation:

It is a double displacement reaction, where positive charged elements change their negative pairs.

What I mean is:
"Cu"^(+2) "O"^(-2)+ "H"^(+1)"Cl"^(-1) rarr "CuCl"_2 + "OH"

But we need to balance it so:
"CuO" + 2"HCl" rarr "CuCl"_2 + "H"_2"O"

This happens because the products have an extra Chlorine ("Cl") so we multiply "HCl" by 2 and, therefore, add a Hydrogen ("H") to the products, as well.