Question

How many grams of CaCl2 would you use to make 500 ml of a 6mM calcium salt solution? CaCl2=110

Answer 1

`0.33g`

Explanation:

Since `n=cV`,

`n(CaCl_2) = 0.5 dm^3*0.006M = 3xx10^-3 mol`

Finally, since `M=nMr`,

`M(CaCl_2) = 3xx10^-3 mol*110gmol^-1 = 0.33g`