How many grams of CaCl2 would you use to make 500 ml of a 6mM calcium salt solution? CaCl2=110

1 Answer
Feb 25, 2018

0.33g

Explanation:

Since n=cV,

n(CaCl_2) = 0.5 dm^3*0.006M = 3xx10^-3 mol

Finally, since M=nMr,

M(CaCl_2) = 3xx10^-3 mol*110gmol^-1 = 0.33g