Question

What is the average rate of change of the function on the given interval?

`f(x)=sqrt(x+1)` on the interval `[0, 3]`

Answer 1

`1/3`

Explanation:

Avg rate of change`=[f(b)-f(a)]/(b-a)`
so in this case:
`f(x) = sqrt(x+1)` , on interval `[0,3]`
`f(0)=1`
`f(3)=2`
so the average rate of change:
`=(2-1)/(3-0)=1/3`