How do you solve #|- \frac { 4x - 5} { 7} | \geq 2#?

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Answer 1 · 2018-02-27T11:21:14

Solution: # x <= -2.25 and x >= 4.75#
In interval notation: # x| (-oo, -2.25] uu[4.65,oo)#

A) #|- ((4x-5)/7)|>=2# or

#- ((4x-5)/7) >=2 or (4x-5)/7 <= -2# or

# 4x-5 <= -14# or # 4x <= -9# or

# x <= -9/4 or x <= -2.25# OR

B) #|- ((4x-5)/7)|>=2# or

#- ((4x-5)/7) <= -2 or (4x-5)/7 >= 2# or

#(4x-5) >= 14 or 4x >=19# or

#x>=19/4 or x >= 4.75 #

Solution: # x <= -2.25 and x >= 4.75#

In interval notation: # x| (-oo, -2.25] uu[4.65,oo)# [Ans]