What is the percent by mass of each element in #"N"_2"O"_3#?

1 Answer
1s2s2p
Feb 27, 2018

#"Percent by mass of N"~~36.8%#

#"Percent by mass of O"~~63.2%#

Explanation:

#"Percent by mass of an element"=(SigmaM_r(X))/M_r*100%# where:

  • #SigmaM_r(X)# = sum of molar masses of an element #X# (#gcolor(white)(l)mol^-1#)
  • #M_r# = molar mass of the compound (#gcolor(white)(l)mol^-1#)

#"Percent by mass of N"=(SigmaM_r("N"))/M_r*100%=(2(14))/(2(14)+3(16))*100%=28/76*100%=700/19%~~36.8%#

#"Percent by mass of O"=(SigmaM_r("O"))/M_r*100%=(3(16))/(2(14)+3(16))*100%=48/76*100%=1200/19%~~63.2%#

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