What is the empirical formula and empirical formula mass for C9H27O9?

1 Answer
zhirou
Feb 28, 2018

Empirical formula: #CH_3O#
Empirical formula mass: #"31.034 g"#

Explanation:

The empirical formula, essentially, is just the molecular formula in simplest terms.
This means that we can divide every subscript of the molecular formula by their greatest common factor to find the empirical formula.

So, for us, this factor would be #9#—after dividing every subscript in #C_9H_27O_9#, we end up with #CH_3O#.

The molar mass of this formula is the amount of mass in #1# mole of #CH_3O#.
To get that, we need to add the masses of #1# mole of carbon, #3# moles of hydrogen, and #1# mole of oxygen.

#12.01+3xx1.008+16.00 = "31.034 g"#

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