How do you write in simplest radical form the coordinates of point A if A is on the terminal side of angle in standard position whose degree measure is #theta#: #OA=2#, #theta=-60^circ#?

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Answer 1 · 2018-02-28T10:20:09

#color(blue)((1,-sqrt(3))#

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Using the sine and cosine functions, the x coordinate is given by:

#x=2cos(-60^@)#

and the y coordinate is given by:

#y=2sin(-60^@)#

#:.#

#x=2sin(-60^@)=2*1/2=1#

#y=2sin(-60^@)=2*-sqrt(3)/2=-sqrt(3)#

#sqrt(3)# is in its simplest form. So coordinates of point #bb(P)# are:

#color(blue)((1,-sqrt(3))#