What's the domain of ?

#sqrt(x+2)/x^3#

1 Answer
Hriman · 1s2s2p
Feb 28, 2018

#D: x>=-2, x!=0#

Explanation:

Since there is a square root in the numerator, and the number inside the square root can't be negative for the domain to be real, set #x+2≥0#
So therefore #x≥-2#
And since x is in the denominator, x can't be 0, or else the function would be undefined

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