Which of the following does not have a noble gas electron configuration?

Question

Which of the following does not have a noble gas electron configuration?

A. $S^{2 -}$ $"S"^(2-)$
B. ${Ba}^{+}$ $"Ba"^+$
C. ${Al}^{3 +}$ $"Al"^(3+)$
D. ${Sb}^{3 -}$ $"Sb"^(3-)$

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Answer 1 · 2018-03-01T00:34:01

${B. Ba}^{+}$ $"B. Ba"^(+)"$

Explanation:

Barium is an alkaline earth metal (group 2/IIA), so it forms ${Ba}^{2 +}$ $"Ba"^(2+)$ ions, which have the noble gas configuration of xenon (Xe). All alkaline earth metals have two valence electrons, which they lose when forming ionic compounds.

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Which of the following does not have a noble gas electron configuration?

A. $S^{2 -}$ $"S"^(2-)$
B. ${Ba}^{+}$ $"Ba"^+$
C. ${Al}^{3 +}$ $"Al"^(3+)$
D. ${Sb}^{3 -}$ $"Sb"^(3-)$

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Explanation:

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Which of the following does not have a noble gas electron configuration?

A. S2−"S"^(2-) B. Ba+"Ba"^+ C. Al3+"Al"^(3+) D. Sb3−"Sb"^(3-)

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Explanation:

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A. $S^{2 -}$ $"S"^(2-)$
B. ${Ba}^{+}$ $"Ba"^+$
C. ${Al}^{3 +}$ $"Al"^(3+)$
D. ${Sb}^{3 -}$ $"Sb"^(3-)$