What Is the quotient of #(x^3 + 6x^2 + 11x + 6) -: (x^2 + 4x + 3)#? Precalculus Real Zeros of Polynomials Synthetic Division 1 Answer Cem Sentin Mar 3, 2018 Quotient is #x+2# Explanation: #x^3+6x^2+11x+6# =#x^3+4x^2+3x+2x^2+8x+6# =#x*(x^2+4x+3)+2*(x^2+4x+3)# =#(x^2+4x+3)*(x+2)# Hence quotient is #x+2# Answer link Related questions What is synthetic division? What are common mistakes students make with synthetic division? How do I find the quotient and remainder using synthetic division? How do you write the remainder in synthetic division? How do I find the quotient #(x^3+5x^2+x-15)/(x+3)# by using synthetic division? How do I find the roots of a polynomial function by using synthetic division? How can synthetic division be used to factor a polynomial? How do I use synthetic division to find #p(-3)# for #p(x)=x^4-2x^3-4x+4#? Use synthetic division to find #p(4)# for #p(x)=x^4-2x^3-4x+4#? How do you use synthetic division to evaluate #f(3)# given that #f(x)=x^3+2x^2-7x+8#? See all questions in Synthetic Division Impact of this question 11672 views around the world You can reuse this answer Creative Commons License