How do you solve #(3\times 3- ( 2+ 1) ) \div ( 5- 2)#?

1 Answer
Advik S.
Mar 3, 2018

#2#, using BODMAS / PEMDAS

Explanation:

BODMAS or PEMDAS rule states the order you have to complete operations in:

#B#rackets
#O#f (powers/exponents)
#D#ivision and #M#ultiplication
#A#ddition and #S#ubtraction

Usually we start with the parentheses within the parentheses. In other words, the smallest brackets.

#(3*3-(2+1))-:(5-2)#

Here, #(2+1)# is the most important parenthesis, and should be solved first:

#(3*3-3)-:(5-2)#

Now, we have two brackets. What do we do?

Remember, multiplication comes before addition or subtraction, so we complete that operation first #(3*3)#

#->(9-3)-:(5-2)#

[note: we do not do division now, as it is an operation outside the parentheses]

Now, we have two subtraction operations. Since both are withing brackets, and both are subtraction, they are on the same level on the BODMAS scale. We do them simultaneously:

#->(6)-:(3)#

We can remove the brackets, as there are no more operations within them:

#->6-:3#

Solve it:

#=2#

Thus, solved.

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