How do you solve |-2x+1|<1?

1 Answer
Mar 3, 2018

x>0andx<1

Explanation:

|M+N|<KhArrM+N<(K)andM+N>(-K)
So,
|-2x+1|<1hArr-2x+1<1and-2x+1>(-1)
hArr-2x<1-1and-2x>(-1)-1
hArr-2x<0and-2x>(-2)
Dividing both sides by (-2),
hArrxcolor(red)(>)0andxcolor(red)(<)1 (ineqalities change)