How do you solve |-2x+1|<1? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer maganbhai P. Mar 3, 2018 x>0andx<1 Explanation: |M+N|<KhArrM+N<(K)andM+N>(-K) So, |-2x+1|<1hArr-2x+1<1and-2x+1>(-1) hArr-2x<1-1and-2x>(-1)-1 hArr-2x<0and-2x>(-2) Dividing both sides by (-2), hArrxcolor(red)(>)0andxcolor(red)(<)1 (ineqalities change) Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve |a+1|\le 4? How do you solve |-6t+3|+9 \ge 18? How do you graph |7x| \ge 21? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given |\frac{2x}{7}+9 | > frac{5}{7}? How do you solve abs(2x-3)<=4? How do you solve abs(2-x)>abs(x+1)? How do you solve this absolute-value inequality 6abs(2x + 5 )> 66? See all questions in Absolute Value Inequalities Impact of this question 2566 views around the world You can reuse this answer Creative Commons License