Find the differential of y in the function: y=x^3cosx ?

1 Answer
Mar 4, 2018

dy/dx=3x^2cos(x)-x^3sin(x)

Explanation:

We want to find the derivative of

y=x^3cos(x)

Use the product rule, if y=f*g

then dy/dx=f'*g+f*g', thus

  • f=x^3=>f'=3x^2
  • g=cos(x)=>g'=-sin(x)

By the product rule

dy/dx=3x^2cos(x)-x^3sin(x)