How do you solve #-22= 2( u - 6) - 4u#?

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Answer 1 · 2018-03-04T12:31:26

#u = 5#

#−22=2(u−6)−4u# Solve for #u#

1) Clear the parentheses
#−22=2u−12−4u#

2) Combine like terms
#−22=- 2u−12#

3) Add #12# to both sides to isolate the #-2u# term
#- 10 = - 2u#

4) Divide both sides by #-2# to isolate #u#
#5 = u# #larr# answer

Answer:
#u = 5#

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Check

Sub in #5# for #u# in the original equation

#−22=2(u−6)−4 u#
#−22=2(5−6)−4(5)#

1) Solve inside the parentheses
#−22=2 ("-"1)−4 (5)#

2) Clear the parentheses
#−22=-2−20#

3) Combine like terms
#-22 = -22#

#Check#