Question

If a projectile is shot at a velocity of `3 m/s` and an angle of `pi/3`, how far will the projectile travel before landing?

Answer 1

The projectile will have a net displacement along horizontal direction only,as because initially it will rise vertically but then will come down due to the effects of gravity.

So,range of projectile motion `R= (u^2 sin 2 theta)/g`(where, `u` is the velocity of projection and `theta` is the angle of projection

Given, `u=3ms^-1,theta=pi/3`

So,putting the values,we get, `R=0.8m`